伪代码进制转换c语言实现

以下是将一个十进制数转换为任意进制的C语言实现。其中，输入的十进制数为decimal，目标进制为base，输出结果存储在字符数组result中。

void decimalToBase(int decimal, int base, char* result) {
    const char digit[] = "0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ";
    int quotient = decimal;
    int remainder;
    int i = 0;

    if (decimal == 0) {
        result[0] = '0';
        result[1] = '\0';
        return;
    }

    while (quotient != 0) {
        remainder = quotient % base;
        result[i++] = digit[remainder];
        quotient /= base;
    }

    result[i] = '\0';

    // Reverse the result
    for (int j = 0; j < i / 2; j++) {
        char temp = result[j];
        result[j] = result[i - j - 1];
        result[i - j - 1] = temp;
    }
}

调用该函数的示例代码：

#include <stdio.h>
#include <string.h>

int main() {
    int decimal = 12345;
    int base = 16;
    char result[100];

    decimalToBase(decimal, base, result);
    printf("%d in base %d is %s\n", decimal, base, result);

    return 0;
}

以上代码的输出结果是：

12345 in base 16 is 3039